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Use Silver nitrate.
A yellow precipitate of silver iodide will form /
AgNO3 + I^- = AgI(s) + NO3^-
This is one of the classic tests for halogens.
lenpollock
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Why does silver nitrate test provide negative result on the presence of a chloride ion?
Due to presence of chloride ion
What will the charge be on an ion formed from iodine?
as ions they are named Iodide.... charge is -1
When iodine becomes an ion is the ion larger or smaller?
Iodine gains one electron to form iodide ion. The size of iodide ion is larger than the size of iodine atom.
Is iodine reducing agent?
no its not, the iodide ion is
What is the formula produce for barium ion with iodide ion?
BaI2 is formed from Ba2+ and 2 I-
What color flame test does the iodide solution give in flame test?
It is not the anions (e.g. iodide) that are responsible for the flame test color, rather the cations such as sodium ion, potassium ion and calcium ion give you different colors.
Why does silver nitrate test provide negative result on the presence of a chloride ion?
Due to presence of chloride ion
What is the formula for iodide?
Iodide ion : I-
Why test sodium peroxoborate with sulphuric acid and potassium iodide?
It's a qualaitative test to test for the presence of the borate anion in the solution
What is the lewis symbol for iodide ion?
Roughly, the iodide ion appears as shown below: .. - :I: ..
How do you test for the presence of iodine?
Testing for Iodide, I-Sodium iodide, NaI, is the source of iodide anion for this experiment.Reaction with bleach involves three steps. The brown color shows the presence of I3- ions.Hypochlorite ion yields chlorine:OCl- (aq) + Cl- (aq) + H2OCl2 (aq) + 2 OH-Chlorine reacts with iodide anion:Cl2 (aq) + 2 I- (aq)I2 (aq) + 2 Cl- (aq)Triiodide ion is formed:I2 (aq) + I- (aq) I3- (aq)Starch reacts with iodine and iodide to form a characteristic blue/black complex. A corn starch packing peanut is shown here.Silver ion reacts with iodide to form silver iodide, AgI.Ag+ (aq) + I- (aq) AgI (s)Reaction of iodide with sulfuric acid produces hydrogen sulfide gas and brown triiodide solution in a series of reactions:I- (aq) + H2SO4 (aq) HI (aq) + HSO4- (aq)8 HI + H2SO4 (aq) H2S (g) + 4 I2 (aq) + 4 H2OI2 (aq) + I- (aq) I3- (aq)Again, starch is used to confirm the presence of iodine and iodide.
