The balanced chemical equation for the reaction between Al and O2 is:
4Al + 3O2 -> 2Al2O3
Therefore, the coefficient needed for Al to balance the equation is 4.
You need 4Al and 3O2 This will give you 2 Al2O3
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
2Al + 3H2O ---> Al2O3 + 3H2
The balanced equation is 3 Fe3O4 + 8 Al -> 4 Al2O3 + 9 Fe. Therefore, the coefficient of Fe is 9.
3FeO4 + 8Al --> 3Fe + 4Al2O3
Al2O3 + 6HBr = 2Albr3 + 3H2O
Al2O3 + H2SO4 = Al2(SO4)3 + H2O
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
2hcl
Mn2O7+Al=
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.